Answer: The nature of the roots are unequal and not real i.e. imaginary roots.

What are the roots of 3×2 2x 1 0?

We know that roots of a quadratic equation and zeros of the corresponding quadratic polynomial are the same. Thus option c is the correct option since these values are the roots of the quadratic equation 3×2−2x−1=0. Thus the zeros of the corresponding quadratic polynomial will be the same.

Why do you set quadratic equations to zero?

You “solve” a quadratic equation by figuring out “WHEN Y=0 what does X equal?”(x,0). That’s why you set the equation to 0 and not any other number; to find the X-intercept(s) aka (x, 0) point(s).

What is the nature of the roots in equation x2 2x 5 0?

x2 + 2x + 5 = 0 Double root real and rational root real and irrational root non-real root.

How to calculate factor 3×2-2x-5?

For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 3⋅−5 = −15 a ⋅ c = 3 ⋅ – 5 = – 15 and whose sum is b = −2 b = – 2. Tap for more steps… Factor − 2 – 2 out of − 2 x – 2 x.

How to solve the equation for X ^ 2-3x = 0?

x2 −3x = 0. As x is the common factor between the 2 values, we factorize the equation by taking x out of x2 − 3x = 0. x2 −3x = 0. x(x −3) = 0. Any value that is multiplied by 0, will give 0 as the answer. 1×0=0. 2×0=0. 3×0=0. From here, we know that in x(x − 3) = 0,

Do you have to factorize the equation to find the answer?

This is a mistake because we CANNOT divide by x unless we are sure about it not being equal to zero. To find x, we first have to factorize the equation. Any value that is multiplied by 0, will give 0 as the answer.

How to calculate the distributive property of 3×2?

3×2+(3−5)x−53×2+(3-5)x-5 Apply the distributive property. 3×2+3x−5x−53×2+3x-5x-5 3×2+3x−5x−53×2+3x-5x-5 Factorout the greatest common factorfrom each group. Tap for more steps… Group the first two termsand the last two terms. (3×2+3x)−5x−5(3×2+3x)-5x-5 Factorout the greatest common factor(GCF) from each group. 3x(x+1)−5(x+1)3x(x+1)-5(x+1)